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-0.27x^2+3.3x+79=0
a = -0.27; b = 3.3; c = +79;
Δ = b2-4ac
Δ = 3.32-4·(-0.27)·79
Δ = 96.21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.3)-\sqrt{96.21}}{2*-0.27}=\frac{-3.3-\sqrt{96.21}}{-0.54} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.3)+\sqrt{96.21}}{2*-0.27}=\frac{-3.3+\sqrt{96.21}}{-0.54} $
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